10c^2+29c+10=

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Solution for 10c^2+29c+10= equation:


Simplifying
10c2 + 29c + 10 = 0

Reorder the terms:
10 + 29c + 10c2 = 0

Solving
10 + 29c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + 2c)(2 + 5c) = 0

Subproblem 1

Set the factor '(5 + 2c)' equal to zero and attempt to solve: Simplifying 5 + 2c = 0 Solving 5 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 2c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 2c = 0 + -5 2c = 0 + -5 Combine like terms: 0 + -5 = -5 2c = -5 Divide each side by '2'. c = -2.5 Simplifying c = -2.5

Subproblem 2

Set the factor '(2 + 5c)' equal to zero and attempt to solve: Simplifying 2 + 5c = 0 Solving 2 + 5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 5c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 5c = 0 + -2 5c = 0 + -2 Combine like terms: 0 + -2 = -2 5c = -2 Divide each side by '5'. c = -0.4 Simplifying c = -0.4

Solution

c = {-2.5, -0.4}

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